If earth has a mass nine times and radius twice to the of a planet P. Then
ms -1 will be the minimum velocity required by a rocket to pull out of gravitational force of P, where v e is escape velocity on earth. The value of x is
Text Solution
Verified by ExpertsThe correct answer is:
A


Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
An object is kept at rest at a distance of 3R above the earth's surface where R is earth's radius. …
Three identical spheres of mass m, are placed at the vertices of an equilateral triangle of length …
Match the LIST-I with LIST-II
List - IList - IIA.Gravitational constant1.B.Gravitational potential …
A satellite of mass 1000 kg is launched to revolve around the earth in an orbit at a height of 270 …
Match the LIST-I with LIST-II
List - IList - IIA.Gravitational constant1.B.Gravitational potential …
A planet has double the mass of the earth. Its average density is equal to that of the earth. An ob…